怎么证明向量场的势函数为调和函数
设P = X ^ 2-Y ^ 2 + X,Q = - (2XY + Y).EQ / EX-EP / EY =-2Y-(-2Y)= 0罗塔= 0 EP / EX + EQ,/ EY = 2X +1 +(2X-1)= 0 DIVA = 0,所以一架飞机谐场.接入点(X0,Y0)=(0,0),力函数u =∫0dx +∫(范围从0到y)(X ^ 2-Y ^ 2 + X)DY = YX ^ 2 + Y ^ 3 / 3 + XY + C.势函数V = - ∫(范围从0到x)(X ^ 2 + X)DX +∫(范围0到y)(2XY + Y)DY-X ^ 3/3-x ^ 2/2 + XY ^ 2 + Y ^ 2/2 + C.瑞瑞爱吃桃2023-05-20 17:38:211